Chemistry 2B Lab Manual Standard Operating Procedures Winter Quarter 2018 Department of Chemistry University of California - Davis Davis, CA 95616. Revision Date 12/1. Department of Chemistry (859) 257-4741 125 Chemistry/Physics Building Lexington KY. Truman State University CHEM 222 Lab Manual Revised 01/09/17 - do not dilute yet. This will be referred to as the 'prepared unknown'. Into five 100 mL volumetric flasks, pipet (volumetrically) 1, 5, 10, 25, and 50 mL portions of the standard iron solution. Lab Manual: Cooper, M., Cooperative Chemistry Laboratory Manual; 4 th edition. Corequisite: CHEM 105, General Chemistry I. Welcome to Chemistry 107, General Chemistry Lab I. Chemistry is an important science involved in many areas, as chemists seek means to improve the quality of life. From the food we eat, to the clothes we wear, to energy.
Experimental Data and Results
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For each problem, find the ΔH for the target reaction below, given the following step reactions and subsequent ΔH values: Elephant man script pdf.
Problem 1 | ||
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Target Reaction: | PCl5(g) → PCl3(g) + Cl2(g) | |
Step Reactions: | P4(s) + 6Cl2(g) → 4PCl3(g) | ΔH = -2439 kJ |
4PCl5(g) → P4(s) + 10Cl2(g) | ΔH = 3438 kJ | |
Answer______________ |
Problem 2 | ||
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Target Reaction: | 2CO2(g) + H2O(g) → C2H2(g) + 5/2O2(g) | |
Step Reactions: | C2H2(g) + 2H2(g) → C2H6(g) | ΔH = -94.5 kJ |
H2O(g) → H2(g) + 1/2O2 (g) | ΔH = 71.2 kJ | |
2C2H6(g) + 7O2(g) → 4CO2(g) + 6H2O(g) | ΔH =-566 kJ | |
Answer______________ |
Problem 3 | ||
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Target Reaction: | N2H4(l) + H2(g) → 2NH3(g) | |
Step Reactions: | N2H4(l) + CH4O(l) → CH2O(g) + N2(g) + 3H2 (g) | ΔH = -37 kJ |
N2(g) + 3H2(g) → 2NH3(g) | ΔH = -46 kJ | |
CH4O(l) → CH2O(g) + H2(g) | ΔH = -65 kJ | |
Answer______________ |
Problem 4 | ||
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Target Reaction: | H2SO4(l) → SO3(g) + H2O(g) | |
Step Reactions: | H2S(g) + 2O2(g) → H2SO4(l) | ΔH = -235.5 kJ |
H2S(g) + 2O2(g) → SO3(g) + H2O(l) | ΔH = -207 kJ | |
H2O(l) → H2O(g) | ΔH = 44 kJ | |
Answer______________ |
Problem 5 | ||
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Target Reaction: | 2C2H4O(l) + 2H2O(l) → 2C2H6O(l) + O2(g) | |
Step Reactions: | C2H6O(l) + 3O2(g) → 2CO2(g) + 3H2O(l) | ΔH = -685 kJ |
C2H4O(l) + 5/2O2(g) → 2CO2(g) + 2H2O(l) | ΔH = -583.5 kJ | |
Answer______________ |
Problem 6 | ||
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Target Reaction: | N2(g) + 2O2(g) → 2NO2(g) | |
Step Reactions: | N2(g) + 3H2(g) → 2NH3(g) | ΔH = -115 kJ |
2NH3(g) + 4H2O(l) → 2NO2(g) + 7H2(g) | ΔH = -142.5 kJ | |
H2O(l) → H2(g) + 1/2O2(g) | ΔH = -43.7 kJ | |
Answer______________ |
Problem 7 | ||
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Target Reaction: | CO2(g) → C(s) + O2(g) | |
Step Reactions: | H2O(l) → H2(g) + 1/2O2(g) | ΔH = 643 kJ |
C2H6(g) → 2C(s) + 3H2(g) | ΔH = 190.6 kJ | |
2CO2(g) + 3H2O(l) → C 2H6(g) + 7/2O2(g) | ΔH = 3511.1 kJ | |
Answer______________ |
Problem 8 | ||
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Target Reaction: | N2H4(l) + CH4O(l) → CH2O(g) + N2(g) + 3H2 (g) | |
Step Reactions: | 2NH3(g) → N2H4(l) + H2(g) | ΔH = 22.5 kJ |
2NH3(g) → N2(g) + 3H2(g) | ΔH = 57.5 kJ | |
CH2O(g) + H2(g) → CH4O(l) | ΔH = 81.2 kJ | |
Answer______________ |
Problem 9 | ||
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Target Reaction: | 1/2H2(g) + 1/2Cl2(g) → HCl(g) | |
Step Reactions: | COCl2(g) + H2O(l) → CH2Cl2(l) + O2(g) | ΔH = -47.5 kJ |
2HCl(g) + 1/2O2(g) → H2O(l) + Cl2(g) | ΔH = 105 kJ | |
CH2Cl2(l) + H2(g) + 3/2O2(g) → COCl2(g) + 2H2O(l) | ΔH = -402.5 kJ | |
Answer______________ |
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Problem 10 | ||
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Target Reaction: | C2H2(g) + 5/2O2(g) → 2CO2(g) + H2O(g) | |
Step Reactions: | C2H6(g) → C2H2(g) + 2H2(g) | ΔH = 283.5 kJ |
H2(g) + 1/2O2(g) → H2O(g) | ΔH = -213.7 kJ | |
2CO2(g) + 3H2O(g) → C2H6(g) + 7/2O2(g) | ΔH = 849 kJ | |
Answer______________ |
Problem 11 | ||
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Target Reaction: | HCl(g) + NaNO2(s) → HNO2(l) + NaCl(s) | |
Step Reactions: | 2NaCl(s) + H2O(l) → 2HCl(g) + Na2O(s) | ΔH = 507 kJ |
NO(g) + NO2(g) + Na2O(s) → 2NaNO2(s) | ΔH = -427 kJ | |
NO(g) + NO2(g) → N2O(g) + O2(g) | ΔH = -43 kJ | |
2HNO2(l) → N2O(g) + O2(g) + H2O(l) | ΔH = 34 kJ | |
Answer______________ |
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Problem 12 | ||
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Target Reaction: | Zn(s) + 1/8S8(s) + 2O2(g) → ZnSO4(s) | |
Step Reactions: | Zn(s) + 1/8S8(s) → ZnS(s) | ΔH = -183.92 kJ |
2ZnS(s) + 3O2(g) → 2ZnO(s) + 2SO2(g) | ΔH = -927 kJ | |
2SO2(g) + O2(g) → 2SO3(g) | ΔH = -196.04 kJ | |
ZnO(s) + SO3(g) → ZnSO4 (s) | ΔH = -230.32 kJ | |
Answer______________ |